\(\int \frac {1}{\sqrt [4]{1-x} (e x)^{13/2} \sqrt [4]{1+x}} \, dx\) [912]

Optimal result

Integrand size = 24, antiderivative size = 76 \[ \int \frac {1}{\sqrt [4]{1-x} (e x)^{13/2} \sqrt [4]{1+x}} \, dx=-\frac {2 \left (1-x^2\right )^{3/4}}{3 e (e x)^{11/2}}+\frac {16 \left (1-x^2\right )^{7/4}}{21 e (e x)^{11/2}}-\frac {64 \left (1-x^2\right )^{11/4}}{231 e (e x)^{11/2}} \]

[Out]

-2/3*(-x^2+1)^(3/4)/e/(e*x)^(11/2)+16/21*(-x^2+1)^(7/4)/e/(e*x)^(11/2)-64/231*(-x^2+1)^(11/4)/e/(e*x)^(11/2)

Rubi [A] (verified)

Time = 0.02 (sec) , antiderivative size = 76, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {126, 279, 270} \[ \int \frac {1}{\sqrt [4]{1-x} (e x)^{13/2} \sqrt [4]{1+x}} \, dx=-\frac {64 \left (1-x^2\right )^{11/4}}{231 e (e x)^{11/2}}+\frac {16 \left (1-x^2\right )^{7/4}}{21 e (e x)^{11/2}}-\frac {2 \left (1-x^2\right )^{3/4}}{3 e (e x)^{11/2}} \]

[In]

Int[1/((1 - x)^(1/4)*(e*x)^(13/2)*(1 + x)^(1/4)),x]

[Out]

(-2*(1 - x^2)^(3/4))/(3*e*(e*x)^(11/2)) + (16*(1 - x^2)^(7/4))/(21*e*(e*x)^(11/2)) - (64*(1 - x^2)^(11/4))/(23
1*e*(e*x)^(11/2))

Rule 126

Int[((f_.)*(x_))^(p_.)*((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[(a*c + b*d*x^2)
^m*(f*x)^p, x] /; FreeQ[{a, b, c, d, f, m, n, p}, x] && EqQ[b*c + a*d, 0] && EqQ[n, m] && GtQ[a, 0] && GtQ[c,
0]

Rule 270

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c*x)^(m + 1)*((a + b*x^n)^(p + 1)/(a*
c*(m + 1))), x] /; FreeQ[{a, b, c, m, n, p}, x] && EqQ[(m + 1)/n + p + 1, 0] && NeQ[m, -1]

Rule 279

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(-(c*x)^(m + 1))*((a + b*x^n)^(p + 1)/
(a*c*n*(p + 1))), x] + Dist[(m + n*(p + 1) + 1)/(a*n*(p + 1)), Int[(c*x)^m*(a + b*x^n)^(p + 1), x], x] /; Free
Q[{a, b, c, m, n, p}, x] && ILtQ[Simplify[(m + 1)/n + p + 1], 0] && NeQ[p, -1]

Rubi steps \begin{align*} \text {integral}& = \int \frac {1}{(e x)^{13/2} \sqrt [4]{1-x^2}} \, dx \\ & = -\frac {2 \left (1-x^2\right )^{3/4}}{3 e (e x)^{11/2}}-\frac {8}{3} \int \frac {\left (1-x^2\right )^{3/4}}{(e x)^{13/2}} \, dx \\ & = -\frac {2 \left (1-x^2\right )^{3/4}}{3 e (e x)^{11/2}}+\frac {16 \left (1-x^2\right )^{7/4}}{21 e (e x)^{11/2}}+\frac {32}{21} \int \frac {\left (1-x^2\right )^{7/4}}{(e x)^{13/2}} \, dx \\ & = -\frac {2 \left (1-x^2\right )^{3/4}}{3 e (e x)^{11/2}}+\frac {16 \left (1-x^2\right )^{7/4}}{21 e (e x)^{11/2}}-\frac {64 \left (1-x^2\right )^{11/4}}{231 e (e x)^{11/2}} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.19 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.46 \[ \int \frac {1}{\sqrt [4]{1-x} (e x)^{13/2} \sqrt [4]{1+x}} \, dx=-\frac {2 x \left (1-x^2\right )^{3/4} \left (21+24 x^2+32 x^4\right )}{231 (e x)^{13/2}} \]

[In]

Integrate[1/((1 - x)^(1/4)*(e*x)^(13/2)*(1 + x)^(1/4)),x]

[Out]

(-2*x*(1 - x^2)^(3/4)*(21 + 24*x^2 + 32*x^4))/(231*(e*x)^(13/2))

Maple [A] (verified)

Time = 1.52 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.43

method	result	size
gosper	\(-\frac {2 x \left (1-x \right )^{\frac {3}{4}} \left (1+x \right )^{\frac {3}{4}} \left (32 x^{4}+24 x^{2}+21\right )}{231 \left (e x \right )^{\frac {13}{2}}}\)	\(33\)
risch	\(\frac {2 \left (e^{2} x^{2} \left (1-x \right ) \left (1+x \right )\right )^{\frac {1}{4}} \left (1+x \right )^{\frac {3}{4}} \left (-1+x \right ) \left (32 x^{4}+24 x^{2}+21\right )}{231 \sqrt {e x}\, \left (1-x \right )^{\frac {1}{4}} e^{6} x^{5} \left (-e^{2} x^{2} \left (-1+x \right ) \left (1+x \right )\right )^{\frac {1}{4}}}\)	\(74\)

[In]

int(1/(1-x)^(1/4)/(e*x)^(13/2)/(1+x)^(1/4),x,method=_RETURNVERBOSE)

[Out]

-2/231*x*(1-x)^(3/4)*(1+x)^(3/4)/(e*x)^(13/2)*(32*x^4+24*x^2+21)

Fricas [A] (verification not implemented)

none

Time = 0.22 (sec) , antiderivative size = 37, normalized size of antiderivative = 0.49 \[ \int \frac {1}{\sqrt [4]{1-x} (e x)^{13/2} \sqrt [4]{1+x}} \, dx=-\frac {2 \, {\left (32 \, x^{4} + 24 \, x^{2} + 21\right )} \sqrt {e x} {\left (x + 1\right )}^{\frac {3}{4}} {\left (-x + 1\right )}^{\frac {3}{4}}}{231 \, e^{7} x^{6}} \]

[In]

integrate(1/(1-x)^(1/4)/(e*x)^(13/2)/(1+x)^(1/4),x, algorithm="fricas")

[Out]

-2/231*(32*x^4 + 24*x^2 + 21)*sqrt(e*x)*(x + 1)^(3/4)*(-x + 1)^(3/4)/(e^7*x^6)

Sympy [F(-1)]

Timed out. \[ \int \frac {1}{\sqrt [4]{1-x} (e x)^{13/2} \sqrt [4]{1+x}} \, dx=\text {Timed out} \]

[In]

integrate(1/(1-x)**(1/4)/(e*x)**(13/2)/(1+x)**(1/4),x)

[Out]

Timed out

Maxima [F]

\[ \int \frac {1}{\sqrt [4]{1-x} (e x)^{13/2} \sqrt [4]{1+x}} \, dx=\int { \frac {1}{\left (e x\right )^{\frac {13}{2}} {\left (x + 1\right )}^{\frac {1}{4}} {\left (-x + 1\right )}^{\frac {1}{4}}} \,d x } \]

[In]

integrate(1/(1-x)^(1/4)/(e*x)^(13/2)/(1+x)^(1/4),x, algorithm="maxima")

[Out]

integrate(1/((e*x)^(13/2)*(x + 1)^(1/4)*(-x + 1)^(1/4)), x)

Giac [F]

\[ \int \frac {1}{\sqrt [4]{1-x} (e x)^{13/2} \sqrt [4]{1+x}} \, dx=\int { \frac {1}{\left (e x\right )^{\frac {13}{2}} {\left (x + 1\right )}^{\frac {1}{4}} {\left (-x + 1\right )}^{\frac {1}{4}}} \,d x } \]

[In]

integrate(1/(1-x)^(1/4)/(e*x)^(13/2)/(1+x)^(1/4),x, algorithm="giac")

[Out]

integrate(1/((e*x)^(13/2)*(x + 1)^(1/4)*(-x + 1)^(1/4)), x)

Mupad [B] (verification not implemented)

Time = 1.30 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.68 \[ \int \frac {1}{\sqrt [4]{1-x} (e x)^{13/2} \sqrt [4]{1+x}} \, dx=-\frac {\sqrt {e\,x}\,\left (\frac {2}{11\,e^7}+\frac {2\,x^2}{77\,e^7}+\frac {16\,x^4}{231\,e^7}-\frac {64\,x^6}{231\,e^7}\right )}{x^6\,{\left (1-x\right )}^{1/4}\,{\left (x+1\right )}^{1/4}} \]

[In]

int(1/((e*x)^(13/2)*(1 - x)^(1/4)*(x + 1)^(1/4)),x)

[Out]

-((e*x)^(1/2)*(2/(11*e^7) + (2*x^2)/(77*e^7) + (16*x^4)/(231*e^7) - (64*x^6)/(231*e^7)))/(x^6*(1 - x)^(1/4)*(x
+ 1)^(1/4))